8(u-1)-10=2(u+3)+6

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Solution for 8(u-1)-10=2(u+3)+6 equation: 



8(u-1)-10=2(u+3)+6

We move all terms to the left:

8(u-1)-10-(2(u+3)+6)=0

We multiply parentheses

8u-(2(u+3)+6)-8-10=0



We calculate terms in parentheses: -(2(u+3)+6), so:

2(u+3)+6

We multiply parentheses

2u+6+6

We add all the numbers together, and all the variables

2u+12

Back to the equation:

-(2u+12)



We add all the numbers together, and all the variables

8u-(2u+12)-18=0

We get rid of parentheses

8u-2u-12-18=0

We add all the numbers together, and all the variables

6u-30=0

We move all terms containing u to the left, all other terms to the right

6u=30

u=30/6

u=5

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