8(t-5)+4t=6(2t+4)-10

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Solution for 8(t-5)+4t=6(2t+4)-10 equation: 



8(t-5)+4t=6(2t+4)-10

We move all terms to the left:

8(t-5)+4t-(6(2t+4)-10)=0

We add all the numbers together, and all the variables

4t+8(t-5)-(6(2t+4)-10)=0

We multiply parentheses

4t+8t-(6(2t+4)-10)-40=0



We calculate terms in parentheses: -(6(2t+4)-10), so:

6(2t+4)-10

We multiply parentheses

12t+24-10

We add all the numbers together, and all the variables

12t+14

Back to the equation:

-(12t+14)



We add all the numbers together, and all the variables

12t-(12t+14)-40=0

We get rid of parentheses

12t-12t-14-40=0

We add all the numbers together, and all the variables

-54!=0

There is no solution for this equation

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