8(t-4)+6t=7(2t+2)-13

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Solution for 8(t-4)+6t=7(2t+2)-13 equation: 



8(t-4)+6t=7(2t+2)-13

We move all terms to the left:

8(t-4)+6t-(7(2t+2)-13)=0

We add all the numbers together, and all the variables

6t+8(t-4)-(7(2t+2)-13)=0

We multiply parentheses

6t+8t-(7(2t+2)-13)-32=0



We calculate terms in parentheses: -(7(2t+2)-13), so:

7(2t+2)-13

We multiply parentheses

14t+14-13

We add all the numbers together, and all the variables

14t+1

Back to the equation:

-(14t+1)



We add all the numbers together, and all the variables

14t-(14t+1)-32=0

We get rid of parentheses

14t-14t-1-32=0

We add all the numbers together, and all the variables

-33!=0

There is no solution for this equation

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