8(t-4)+4t=6(2t+5)-8

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Solution for 8(t-4)+4t=6(2t+5)-8 equation: 



8(t-4)+4t=6(2t+5)-8

We move all terms to the left:

8(t-4)+4t-(6(2t+5)-8)=0

We add all the numbers together, and all the variables

4t+8(t-4)-(6(2t+5)-8)=0

We multiply parentheses

4t+8t-(6(2t+5)-8)-32=0



We calculate terms in parentheses: -(6(2t+5)-8), so:

6(2t+5)-8

We multiply parentheses

12t+30-8

We add all the numbers together, and all the variables

12t+22

Back to the equation:

-(12t+22)



We add all the numbers together, and all the variables

12t-(12t+22)-32=0

We get rid of parentheses

12t-12t-22-32=0

We add all the numbers together, and all the variables

-54!=0

There is no solution for this equation

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