8(t-3)+4t=6(2t+3)-10

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Solution for 8(t-3)+4t=6(2t+3)-10 equation: 


Simplifying
8(t + -3) + 4t = 6(2t + 3) + -10

Reorder the terms:
8(-3 + t) + 4t = 6(2t + 3) + -10
(-3 * 8 + t * 8) + 4t = 6(2t + 3) + -10
(-24 + 8t) + 4t = 6(2t + 3) + -10

Combine like terms: 8t + 4t = 12t
-24 + 12t = 6(2t + 3) + -10

Reorder the terms:
-24 + 12t = 6(3 + 2t) + -10
-24 + 12t = (3 * 6 + 2t * 6) + -10
-24 + 12t = (18 + 12t) + -10

Reorder the terms:
-24 + 12t = 18 + -10 + 12t

Combine like terms: 18 + -10 = 8
-24 + 12t = 8 + 12t

Add '-12t' to each side of the equation.
-24 + 12t + -12t = 8 + 12t + -12t

Combine like terms: 12t + -12t = 0
-24 + 0 = 8 + 12t + -12t
-24 = 8 + 12t + -12t

Combine like terms: 12t + -12t = 0
-24 = 8 + 0
-24 = 8

Solving
-24 = 8

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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