8(t-3)+4=6(2t+1)-10

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Solution for 8(t-3)+4=6(2t+1)-10 equation:


Simplifying
8(t + -3) + 4 = 6(2t + 1) + -10

Reorder the terms:
8(-3 + t) + 4 = 6(2t + 1) + -10
(-3 * 8 + t * 8) + 4 = 6(2t + 1) + -10
(-24 + 8t) + 4 = 6(2t + 1) + -10

Reorder the terms:
-24 + 4 + 8t = 6(2t + 1) + -10

Combine like terms: -24 + 4 = -20
-20 + 8t = 6(2t + 1) + -10

Reorder the terms:
-20 + 8t = 6(1 + 2t) + -10
-20 + 8t = (1 * 6 + 2t * 6) + -10
-20 + 8t = (6 + 12t) + -10

Reorder the terms:
-20 + 8t = 6 + -10 + 12t

Combine like terms: 6 + -10 = -4
-20 + 8t = -4 + 12t

Solving
-20 + 8t = -4 + 12t

Solving for variable 't'.

Move all terms containing t to the left, all other terms to the right.

Add '-12t' to each side of the equation.
-20 + 8t + -12t = -4 + 12t + -12t

Combine like terms: 8t + -12t = -4t
-20 + -4t = -4 + 12t + -12t

Combine like terms: 12t + -12t = 0
-20 + -4t = -4 + 0
-20 + -4t = -4

Add '20' to each side of the equation.
-20 + 20 + -4t = -4 + 20

Combine like terms: -20 + 20 = 0
0 + -4t = -4 + 20
-4t = -4 + 20

Combine like terms: -4 + 20 = 16
-4t = 16

Divide each side by '-4'.
t = -4

Simplifying
t = -4

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