8(t+4)-8(-7t-2)=63(t+1)+7

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Solution for 8(t+4)-8(-7t-2)=63(t+1)+7 equation: 



8(t+4)-8(-7t-2)=63(t+1)+7

We move all terms to the left:

8(t+4)-8(-7t-2)-(63(t+1)+7)=0

We multiply parentheses

8t+56t-(63(t+1)+7)+32+16=0



We calculate terms in parentheses: -(63(t+1)+7), so:

63(t+1)+7

We multiply parentheses

63t+63+7

We add all the numbers together, and all the variables

63t+70

Back to the equation:

-(63t+70)



We add all the numbers together, and all the variables

64t-(63t+70)+48=0

We get rid of parentheses

64t-63t-70+48=0

We add all the numbers together, and all the variables

t-22=0

We move all terms containing t to the left, all other terms to the right

t=22

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