8(t+2)-3(t-4)=8

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Solution for 8(t+2)-3(t-4)=8 equation: 



8(t+2)-3(t-4)=8

We move all terms to the left:

8(t+2)-3(t-4)-(8)=0

We multiply parentheses

8t-3t+16+12-8=0

We add all the numbers together, and all the variables

5t+20=0

We move all terms containing t to the left, all other terms to the right

5t=-20

t=-20/5

t=-4

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