8(t+2)-3(t-4)=6(t-7)=8

Solution for 8(t+2)-3(t-4)=6(t-7)=8 equation:

8(t+2)-3(t-4)=6(t-7)=8

We move all terms to the left:

8(t+2)-3(t-4)-(6(t-7))=0

We multiply parentheses

8t-3t-(6(t-7))+16+12=0


We calculate terms in parentheses: -(6(t-7)), so:

6(t-7)

We multiply parentheses

6t-42

Back to the equation:

-(6t-42)


We add all the numbers together, and all the variables

5t-(6t-42)+28=0

We get rid of parentheses

5t-6t+42+28=0

We add all the numbers together, and all the variables

-1t+70=0

We move all terms containing t to the left, all other terms to the right

-t=-70

t=-70/-1

t=+70