8(t+2)-3(t-4)=6(t-7)+9-t

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Solution for 8(t+2)-3(t-4)=6(t-7)+9-t equation: 



8(t+2)-3(t-4)=6(t-7)+9-t

We move all terms to the left:

8(t+2)-3(t-4)-(6(t-7)+9-t)=0

We multiply parentheses

8t-3t-(6(t-7)+9-t)+16+12=0



We calculate terms in parentheses: -(6(t-7)+9-t), so:

6(t-7)+9-t

determiningTheFunctionDomain
6(t-7)-t+9

We add all the numbers together, and all the variables

-1t+6(t-7)+9

We multiply parentheses

-1t+6t-42+9

We add all the numbers together, and all the variables

5t-33

Back to the equation:

-(5t-33)



We add all the numbers together, and all the variables

5t-(5t-33)+28=0

We get rid of parentheses

5t-5t+33+28=0

We add all the numbers together, and all the variables

61!=0

There is no solution for this equation

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