8(r+6)-10+r=3(r+12)+5r

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Solution for 8(r+6)-10+r=3(r+12)+5r equation: 



8(r+6)-10+r=3(r+12)+5r

We move all terms to the left:

8(r+6)-10+r-(3(r+12)+5r)=0

We add all the numbers together, and all the variables

r+8(r+6)-(3(r+12)+5r)-10=0

We multiply parentheses

r+8r-(3(r+12)+5r)+48-10=0



We calculate terms in parentheses: -(3(r+12)+5r), so:

3(r+12)+5r

We add all the numbers together, and all the variables

5r+3(r+12)

We multiply parentheses

5r+3r+36

We add all the numbers together, and all the variables

8r+36

Back to the equation:

-(8r+36)



We add all the numbers together, and all the variables

9r-(8r+36)+38=0

We get rid of parentheses

9r-8r-36+38=0

We add all the numbers together, and all the variables

r+2=0

We move all terms containing r to the left, all other terms to the right

r=-2

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