8(q-4)=2(q+1)

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Solution for 8(q-4)=2(q+1) equation:



8(q-4)=2(q+1)
We move all terms to the left:
8(q-4)-(2(q+1))=0
We multiply parentheses
8q-(2(q+1))-32=0
We calculate terms in parentheses: -(2(q+1)), so:
2(q+1)
We multiply parentheses
2q+2
Back to the equation:
-(2q+2)
We get rid of parentheses
8q-2q-2-32=0
We add all the numbers together, and all the variables
6q-34=0
We move all terms containing q to the left, all other terms to the right
6q=34
q=34/6
q=5+2/3

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