8(q+1)-5=3(2q-4)-1

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Solution for 8(q+1)-5=3(2q-4)-1 equation: 



8(q+1)-5=3(2q-4)-1

We move all terms to the left:

8(q+1)-5-(3(2q-4)-1)=0

We multiply parentheses

8q-(3(2q-4)-1)+8-5=0



We calculate terms in parentheses: -(3(2q-4)-1), so:

3(2q-4)-1

We multiply parentheses

6q-12-1

We add all the numbers together, and all the variables

6q-13

Back to the equation:

-(6q-13)



We add all the numbers together, and all the variables

8q-(6q-13)+3=0

We get rid of parentheses

8q-6q+13+3=0

We add all the numbers together, and all the variables

2q+16=0

We move all terms containing q to the left, all other terms to the right

2q=-16

q=-16/2

q=-8

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