8(n+3)=7(n-4)

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Solution for 8(n+3)=7(n-4) equation: 



8(n+3)=7(n-4)

We move all terms to the left:

8(n+3)-(7(n-4))=0

We multiply parentheses

8n-(7(n-4))+24=0



We calculate terms in parentheses: -(7(n-4)), so:

7(n-4)

We multiply parentheses

7n-28

Back to the equation:

-(7n-28)



We get rid of parentheses

8n-7n+28+24=0

We add all the numbers together, and all the variables

n+52=0

We move all terms containing n to the left, all other terms to the right

n=-52

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