8(n+2)=4(2n+4)

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Solution for 8(n+2)=4(2n+4) equation: 



8(n+2)=4(2n+4)

We move all terms to the left:

8(n+2)-(4(2n+4))=0

We multiply parentheses

8n-(4(2n+4))+16=0



We calculate terms in parentheses: -(4(2n+4)), so:

4(2n+4)

We multiply parentheses

8n+16

Back to the equation:

-(8n+16)



We get rid of parentheses

8n-8n-16+16=0

We add all the numbers together, and all the variables

=0

n=0/1

n=0

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