8(m+1)=4(2m+2)

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Solution for 8(m+1)=4(2m+2) equation: 


Simplifying
8(m + 1) = 4(2m + 2)

Reorder the terms:
8(1 + m) = 4(2m + 2)
(1 * 8 + m * 8) = 4(2m + 2)
(8 + 8m) = 4(2m + 2)

Reorder the terms:
8 + 8m = 4(2 + 2m)
8 + 8m = (2 * 4 + 2m * 4)
8 + 8m = (8 + 8m)

Add '-8' to each side of the equation.
8 + -8 + 8m = 8 + -8 + 8m

Combine like terms: 8 + -8 = 0
0 + 8m = 8 + -8 + 8m
8m = 8 + -8 + 8m

Combine like terms: 8 + -8 = 0
8m = 0 + 8m
8m = 8m

Add '-8m' to each side of the equation.
8m + -8m = 8m + -8m

Combine like terms: 8m + -8m = 0
0 = 8m + -8m

Combine like terms: 8m + -8m = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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