8(d+2)=4d-12

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Solution for 8(d+2)=4d-12 equation: 



8(d+2)=4d-12

We move all terms to the left:

8(d+2)-(4d-12)=0

We multiply parentheses

8d-(4d-12)+16=0

We get rid of parentheses

8d-4d+12+16=0

We add all the numbers together, and all the variables

4d+28=0

We move all terms containing d to the left, all other terms to the right

4d=-28

d=-28/4

d=-7

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