8(c-9)=6(2c-12)-4c

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Solution for 8(c-9)=6(2c-12)-4c equation: 


Simplifying
8(c + -9) = 6(2c + -12) + -4c

Reorder the terms:
8(-9 + c) = 6(2c + -12) + -4c
(-9 * 8 + c * 8) = 6(2c + -12) + -4c
(-72 + 8c) = 6(2c + -12) + -4c

Reorder the terms:
-72 + 8c = 6(-12 + 2c) + -4c
-72 + 8c = (-12 * 6 + 2c * 6) + -4c
-72 + 8c = (-72 + 12c) + -4c

Combine like terms: 12c + -4c = 8c
-72 + 8c = -72 + 8c

Add '72' to each side of the equation.
-72 + 72 + 8c = -72 + 72 + 8c

Combine like terms: -72 + 72 = 0
0 + 8c = -72 + 72 + 8c
8c = -72 + 72 + 8c

Combine like terms: -72 + 72 = 0
8c = 0 + 8c
8c = 8c

Add '-8c' to each side of the equation.
8c + -8c = 8c + -8c

Combine like terms: 8c + -8c = 0
0 = 8c + -8c

Combine like terms: 8c + -8c = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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