8(c-9)=6(2c+12)-4c

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Solution for 8(c-9)=6(2c+12)-4c equation: 



8(c-9)=6(2c+12)-4c

We move all terms to the left:

8(c-9)-(6(2c+12)-4c)=0

We multiply parentheses

8c-(6(2c+12)-4c)-72=0



We calculate terms in parentheses: -(6(2c+12)-4c), so:

6(2c+12)-4c

We add all the numbers together, and all the variables

-4c+6(2c+12)

We multiply parentheses

-4c+12c+72

We add all the numbers together, and all the variables

8c+72

Back to the equation:

-(8c+72)



We get rid of parentheses

8c-8c-72-72=0

We add all the numbers together, and all the variables

-144!=0

There is no solution for this equation

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