8(c-4)+8=5+c-29

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Solution for 8(c-4)+8=5+c-29 equation: 



8(c-4)+8=5+c-29

We move all terms to the left:

8(c-4)+8-(5+c-29)=0

We add all the numbers together, and all the variables

8(c-4)-(c-24)+8=0

We multiply parentheses

8c-(c-24)-32+8=0

We get rid of parentheses

8c-c+24-32+8=0

We add all the numbers together, and all the variables

7c=0

c=0/7

c=0

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