8(c+9)=6(2c+-12)+4c

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Solution for 8(c+9)=6(2c+-12)+4c equation: 



8(c+9)=6(2c+-12)+4c

We move all terms to the left:

8(c+9)-(6(2c+-12)+4c)=0

We add all the numbers together, and all the variables

8(c+9)-(6(2c-12)+4c)=0

We multiply parentheses

8c-(6(2c-12)+4c)+72=0



We calculate terms in parentheses: -(6(2c-12)+4c), so:

6(2c-12)+4c

We add all the numbers together, and all the variables

4c+6(2c-12)

We multiply parentheses

4c+12c-72

We add all the numbers together, and all the variables

16c-72

Back to the equation:

-(16c-72)



We get rid of parentheses

8c-16c+72+72=0

We add all the numbers together, and all the variables

-8c+144=0

We move all terms containing c to the left, all other terms to the right

-8c=-144

c=-144/-8

c=+18

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