8(b-3)=2(4b+1)

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Solution for 8(b-3)=2(4b+1) equation: 



8(b-3)=2(4b+1)

We move all terms to the left:

8(b-3)-(2(4b+1))=0

We multiply parentheses

8b-(2(4b+1))-24=0



We calculate terms in parentheses: -(2(4b+1)), so:

2(4b+1)

We multiply parentheses

8b+2

Back to the equation:

-(8b+2)



We get rid of parentheses

8b-8b-2-24=0

We add all the numbers together, and all the variables

-26!=0

There is no solution for this equation

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