8(b-3)=-2(b+7)

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Solution for 8(b-3)=-2(b+7) equation: 



8(b-3)=-2(b+7)

We move all terms to the left:

8(b-3)-(-2(b+7))=0

We multiply parentheses

8b-(-2(b+7))-24=0



We calculate terms in parentheses: -(-2(b+7)), so:

-2(b+7)

We multiply parentheses

-2b-14

Back to the equation:

-(-2b-14)



We get rid of parentheses

8b+2b+14-24=0

We add all the numbers together, and all the variables

10b-10=0

We move all terms containing b to the left, all other terms to the right

10b=10

b=10/10

b=1

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