8(b-2)=3b=-9(b-1)

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Solution for 8(b-2)=3b=-9(b-1) equation: 



8(b-2)=3b=-9(b-1)

We move all terms to the left:

8(b-2)-(3b)=0

We add all the numbers together, and all the variables

-3b+8(b-2)=0

We multiply parentheses

-3b+8b-16=0

We add all the numbers together, and all the variables

5b-16=0

We move all terms containing b to the left, all other terms to the right

5b=16

b=16/5

b=3+1/5

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