8(b-12)=-2b-4(b+10)

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Solution for 8(b-12)=-2b-4(b+10) equation: 



8(b-12)=-2b-4(b+10)

We move all terms to the left:

8(b-12)-(-2b-4(b+10))=0

We multiply parentheses

8b-(-2b-4(b+10))-96=0



We calculate terms in parentheses: -(-2b-4(b+10)), so:

-2b-4(b+10)

We multiply parentheses

-2b-4b-40

We add all the numbers together, and all the variables

-6b-40

Back to the equation:

-(-6b-40)



We get rid of parentheses

8b+6b+40-96=0

We add all the numbers together, and all the variables

14b-56=0

We move all terms containing b to the left, all other terms to the right

14b=56

b=56/14

b=4

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