8(b+1)=2+5b

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Solution for 8(b+1)=2+5b equation:


Simplifying
8(b + 1) = 2 + 5b

Reorder the terms:
8(1 + b) = 2 + 5b
(1 * 8 + b * 8) = 2 + 5b
(8 + 8b) = 2 + 5b

Solving
8 + 8b = 2 + 5b

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '-5b' to each side of the equation.
8 + 8b + -5b = 2 + 5b + -5b

Combine like terms: 8b + -5b = 3b
8 + 3b = 2 + 5b + -5b

Combine like terms: 5b + -5b = 0
8 + 3b = 2 + 0
8 + 3b = 2

Add '-8' to each side of the equation.
8 + -8 + 3b = 2 + -8

Combine like terms: 8 + -8 = 0
0 + 3b = 2 + -8
3b = 2 + -8

Combine like terms: 2 + -8 = -6
3b = -6

Divide each side by '3'.
b = -2

Simplifying
b = -2

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