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8(a+3)=(5)(3)
We move all terms to the left:
8(a+3)-((5)(3))=0
determiningTheFunctionDomain 8(a+3)-53=0
We multiply parentheses
8a+24-53=0
We add all the numbers together, and all the variables
8a-29=0
We move all terms containing a to the left, all other terms to the right
8a=29
a=29/8
a=3+5/8
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