8(8+4c)=32

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Solution for 8(8+4c)=32 equation: 



8(8+4c)=32

We move all terms to the left:

8(8+4c)-(32)=0

We add all the numbers together, and all the variables

8(4c+8)-32=0

We multiply parentheses

32c+64-32=0

We add all the numbers together, and all the variables

32c+32=0

We move all terms containing c to the left, all other terms to the right

32c=-32

c=-32/32

c=-1

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