8(6y-3)=12(4y-2)

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Solution for 8(6y-3)=12(4y-2) equation: 



8(6y-3)=12(4y-2)

We move all terms to the left:

8(6y-3)-(12(4y-2))=0

We multiply parentheses

48y-(12(4y-2))-24=0



We calculate terms in parentheses: -(12(4y-2)), so:

12(4y-2)

We multiply parentheses

48y-24

Back to the equation:

-(48y-24)



We get rid of parentheses

48y-48y+24-24=0

We add all the numbers together, and all the variables

=0

y=0/1

y=0

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