8(6a-4)=27-5a

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Solution for 8(6a-4)=27-5a equation: 



8(6a-4)=27-5a

We move all terms to the left:

8(6a-4)-(27-5a)=0

We add all the numbers together, and all the variables

8(6a-4)-(-5a+27)=0

We multiply parentheses

48a-(-5a+27)-32=0

We get rid of parentheses

48a+5a-27-32=0

We add all the numbers together, and all the variables

53a-59=0

We move all terms containing a to the left, all other terms to the right

53a=59

a=59/53

a=1+6/53

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