8(6-4x)+13-4x=12+(2x-4)-3(6-x)

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Solution for 8(6-4x)+13-4x=12+(2x-4)-3(6-x) equation: 



8(6-4x)+13-4x=12+(2x-4)-3(6-x)

We move all terms to the left:

8(6-4x)+13-4x-(12+(2x-4)-3(6-x))=0

We add all the numbers together, and all the variables

8(-4x+6)-4x-(12+(2x-4)-3(-1x+6))+13=0

We add all the numbers together, and all the variables

-4x+8(-4x+6)-(12+(2x-4)-3(-1x+6))+13=0

We multiply parentheses

-4x-32x-(12+(2x-4)-3(-1x+6))+48+13=0



We calculate terms in parentheses: -(12+(2x-4)-3(-1x+6)), so:

12+(2x-4)-3(-1x+6)

determiningTheFunctionDomain
(2x-4)-3(-1x+6)+12

We multiply parentheses

(2x-4)+3x-18+12

We get rid of parentheses

2x+3x-4-18+12

We add all the numbers together, and all the variables

5x-10

Back to the equation:

-(5x-10)



We add all the numbers together, and all the variables

-36x-(5x-10)+61=0

We get rid of parentheses

-36x-5x+10+61=0

We add all the numbers together, and all the variables

-41x+71=0

We move all terms containing x to the left, all other terms to the right

-41x=-71

x=-71/-41

x=1+30/41

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