8(5c-2)=10(32+4c

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Solution for 8(5c-2)=10(32+4c equation: 



8(5c-2)=10(32+4c

We move all terms to the left:

8(5c-2)-(10(32+4c)=0

We add all the numbers together, and all the variables

8(5c-2)-(10(4c+32)=0

We multiply parentheses

40c-(10(4c+32)-16=0

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