8(5-4c)+25c+7(=10

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Solution for 8(5-4c)+25c+7(=10 equation: 



8(5-4c)+25c+7(=10

We move all terms to the left:

8(5-4c)+25c+7(-(10)=0

We add all the numbers together, and all the variables

8(-4c+5)+25c+7(-10=0

We add all the numbers together, and all the variables

25c+8(-4c+5)=0

We multiply parentheses

25c-32c+40=0

We add all the numbers together, and all the variables

-7c+40=0

We move all terms containing c to the left, all other terms to the right

-7c=-40

c=-40/-7

c=5+5/7

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