8(5+4b)+11=6(2-5b)

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Solution for 8(5+4b)+11=6(2-5b) equation: 



8(5+4b)+11=6(2-5b)

We move all terms to the left:

8(5+4b)+11-(6(2-5b))=0

We add all the numbers together, and all the variables

8(4b+5)-(6(-5b+2))+11=0

We multiply parentheses

32b-(6(-5b+2))+40+11=0



We calculate terms in parentheses: -(6(-5b+2)), so:

6(-5b+2)

We multiply parentheses

-30b+12

Back to the equation:

-(-30b+12)



We add all the numbers together, and all the variables

32b-(-30b+12)+51=0

We get rid of parentheses

32b+30b-12+51=0

We add all the numbers together, and all the variables

62b+39=0

We move all terms containing b to the left, all other terms to the right

62b=-39

b=-39/62

b=-39/62

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