8(4y-1)-12y=(2y-6)

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Solution for 8(4y-1)-12y=(2y-6) equation: 



8(4y-1)-12y=(2y-6)

We move all terms to the left:

8(4y-1)-12y-((2y-6))=0

We add all the numbers together, and all the variables

-12y+8(4y-1)-((2y-6))=0

We multiply parentheses

-12y+32y-((2y-6))-8=0



We calculate terms in parentheses: -((2y-6)), so:

(2y-6)

We get rid of parentheses

2y-6

Back to the equation:

-(2y-6)



We add all the numbers together, and all the variables

20y-(2y-6)-8=0

We get rid of parentheses

20y-2y+6-8=0

We add all the numbers together, and all the variables

18y-2=0

We move all terms containing y to the left, all other terms to the right

18y=2

y=2/18

y=1/9

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