8(4y+2)=4(2-1)

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Solution for 8(4y+2)=4(2-1) equation: 



8(4y+2)=4(2-1)

We move all terms to the left:

8(4y+2)-(4(2-1))=0

We add all the numbers together, and all the variables

8(4y+2)-(41)=0

We add all the numbers together, and all the variables

8(4y+2)-41=0

We multiply parentheses

32y+16-41=0

We add all the numbers together, and all the variables

32y-25=0

We move all terms containing y to the left, all other terms to the right

32y=25

y=25/32

y=25/32

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