8(4x-4)=-32+2x

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Solution for 8(4x-4)=-32+2x equation: 



8(4x-4)=-32+2x

We move all terms to the left:

8(4x-4)-(-32+2x)=0

We add all the numbers together, and all the variables

8(4x-4)-(2x-32)=0

We multiply parentheses

32x-(2x-32)-32=0

We get rid of parentheses

32x-2x+32-32=0

We add all the numbers together, and all the variables

30x=0

x=0/30

x=0

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