8(4u-)-12u=11(2u-)

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Solution for 8(4u-)-12u=11(2u-) equation:



8(4u-)-12u=11(2u-)
We move all terms to the left:
8(4u-)-12u-(11(2u-))=0
We add all the numbers together, and all the variables
8(+4u)-12u-(11(+2u))=0
We add all the numbers together, and all the variables
-12u+8(+4u)-(11(+2u))=0
We multiply parentheses
-12u+32u-(11(+2u))=0
We calculate terms in parentheses: -(11(+2u)), so:
11(+2u)
We multiply parentheses
22u
Back to the equation:
-(22u)
We add all the numbers together, and all the variables
-2u=0
u=0/-2
u=0

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