8(4q-5)-7q=(5q-8)

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Solution for 8(4q-5)-7q=(5q-8) equation: 



8(4q-5)-7q=(5q-8)

We move all terms to the left:

8(4q-5)-7q-((5q-8))=0

We add all the numbers together, and all the variables

-7q+8(4q-5)-((5q-8))=0

We multiply parentheses

-7q+32q-((5q-8))-40=0



We calculate terms in parentheses: -((5q-8)), so:

(5q-8)

We get rid of parentheses

5q-8

Back to the equation:

-(5q-8)



We add all the numbers together, and all the variables

25q-(5q-8)-40=0

We get rid of parentheses

25q-5q+8-40=0

We add all the numbers together, and all the variables

20q-32=0

We move all terms containing q to the left, all other terms to the right

20q=32

q=32/20

q=1+3/5

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