8(4a+7c)-6(2a+4c)=0

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Solution for 8(4a+7c)-6(2a+4c)=0 equation: 


Simplifying
8(4a + 7c) + -6(2a + 4c) = 0
(4a * 8 + 7c * 8) + -6(2a + 4c) = 0
(32a + 56c) + -6(2a + 4c) = 0
32a + 56c + (2a * -6 + 4c * -6) = 0
32a + 56c + (-12a + -24c) = 0

Reorder the terms:
32a + -12a + 56c + -24c = 0

Combine like terms: 32a + -12a = 20a
20a + 56c + -24c = 0

Combine like terms: 56c + -24c = 32c
20a + 32c = 0

Solving
20a + 32c = 0

Solving for variable 'a'.

Move all terms containing a to the left, all other terms to the right.

Add '-32c' to each side of the equation.
20a + 32c + -32c = 0 + -32c

Combine like terms: 32c + -32c = 0
20a + 0 = 0 + -32c
20a = 0 + -32c
Remove the zero:
20a = -32c

Divide each side by '20'.
a = -1.6c

Simplifying
a = -1.6c

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