8(3y-2)=3(10y-y)+35

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Solution for 8(3y-2)=3(10y-y)+35 equation: 



8(3y-2)=3(10y-y)+35

We move all terms to the left:

8(3y-2)-(3(10y-y)+35)=0

We add all the numbers together, and all the variables

8(3y-2)-(3(+9y)+35)=0

We multiply parentheses

24y-(3(+9y)+35)-16=0



We calculate terms in parentheses: -(3(+9y)+35), so:

3(+9y)+35

We multiply parentheses

27y+35

Back to the equation:

-(27y+35)



We get rid of parentheses

24y-27y-35-16=0

We add all the numbers together, and all the variables

-3y-51=0

We move all terms containing y to the left, all other terms to the right

-3y=51

y=51/-3

y=-17

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