8(3y-2)+20=5(4y+8)

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Solution for 8(3y-2)+20=5(4y+8) equation: 



8(3y-2)+20=5(4y+8)

We move all terms to the left:

8(3y-2)+20-(5(4y+8))=0

We multiply parentheses

24y-(5(4y+8))-16+20=0



We calculate terms in parentheses: -(5(4y+8)), so:

5(4y+8)

We multiply parentheses

20y+40

Back to the equation:

-(20y+40)



We add all the numbers together, and all the variables

24y-(20y+40)+4=0

We get rid of parentheses

24y-20y-40+4=0

We add all the numbers together, and all the variables

4y-36=0

We move all terms containing y to the left, all other terms to the right

4y=36

y=36/4

y=9

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