8(3x-4)=20x+32

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Solution for 8(3x-4)=20x+32 equation: 



8(3x-4)=20x+32

We move all terms to the left:

8(3x-4)-(20x+32)=0

We multiply parentheses

24x-(20x+32)-32=0

We get rid of parentheses

24x-20x-32-32=0

We add all the numbers together, and all the variables

4x-64=0

We move all terms containing x to the left, all other terms to the right

4x=64

x=64/4

x=16

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