8(3j-2)=4(1+j)

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Solution for 8(3j-2)=4(1+j) equation: 



8(3j-2)=4(1+j)

We move all terms to the left:

8(3j-2)-(4(1+j))=0

We add all the numbers together, and all the variables

8(3j-2)-(4(j+1))=0

We multiply parentheses

24j-(4(j+1))-16=0



We calculate terms in parentheses: -(4(j+1)), so:

4(j+1)

We multiply parentheses

4j+4

Back to the equation:

-(4j+4)



We get rid of parentheses

24j-4j-4-16=0

We add all the numbers together, and all the variables

20j-20=0

We move all terms containing j to the left, all other terms to the right

20j=20

j=20/20

j=1

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