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8(3-x)=2(x-6)
We move all terms to the left:
8(3-x)-(2(x-6))=0
We add all the numbers together, and all the variables
8(-1x+3)-(2(x-6))=0
We multiply parentheses
-8x-(2(x-6))+24=0
We calculate terms in parentheses: -(2(x-6)), so:We get rid of parentheses
2(x-6)
We multiply parentheses
2x-12
Back to the equation:
-(2x-12)
-8x-2x+12+24=0
We add all the numbers together, and all the variables
-10x+36=0
We move all terms containing x to the left, all other terms to the right
-10x=-36
x=-36/-10
x=3+3/5
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