8(3-k)-17=32-5(k-4)

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Solution for 8(3-k)-17=32-5(k-4) equation: 



8(3-k)-17=32-5(k-4)

We move all terms to the left:

8(3-k)-17-(32-5(k-4))=0

We add all the numbers together, and all the variables

8(-1k+3)-(32-5(k-4))-17=0

We multiply parentheses

-8k-(32-5(k-4))+24-17=0



We calculate terms in parentheses: -(32-5(k-4)), so:

32-5(k-4)

determiningTheFunctionDomain
-5(k-4)+32

We multiply parentheses

-5k+20+32

We add all the numbers together, and all the variables

-5k+52

Back to the equation:

-(-5k+52)



We add all the numbers together, and all the variables

-8k-(-5k+52)+7=0

We get rid of parentheses

-8k+5k-52+7=0

We add all the numbers together, and all the variables

-3k-45=0

We move all terms containing k to the left, all other terms to the right

-3k=45

k=45/-3

k=-15

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