8(3+c)=64

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Solution for 8(3+c)=64 equation: 



8(3+c)=64

We move all terms to the left:

8(3+c)-(64)=0

We add all the numbers together, and all the variables

8(c+3)-64=0

We multiply parentheses

8c+24-64=0

We add all the numbers together, and all the variables

8c-40=0

We move all terms containing c to the left, all other terms to the right

8c=40

c=40/8

c=5

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