8(3+3z)+1=z-10(z+1-)

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Solution for 8(3+3z)+1=z-10(z+1-) equation: 



8(3+3z)+1=z-10(z+1-)

We move all terms to the left:

8(3+3z)+1-(z-10(z+1-))=0

We add all the numbers together, and all the variables

8(3z+3)-(z-10(+z))+1=0

We multiply parentheses

24z-(z-10(+z))+24+1=0



We calculate terms in parentheses: -(z-10(+z)), so:

z-10(+z)

We multiply parentheses

z-10z

We add all the numbers together, and all the variables

-9z

Back to the equation:

-(-9z)



We add all the numbers together, and all the variables

24z-(-9z)+25=0

We get rid of parentheses

24z+9z+25=0

We add all the numbers together, and all the variables

33z+25=0

We move all terms containing z to the left, all other terms to the right

33z=-25

z=-25/33

z=-25/33

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