8(2z+4)-3=(3z-6)+5

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Solution for 8(2z+4)-3=(3z-6)+5 equation: 



8(2z+4)-3=(3z-6)+5

We move all terms to the left:

8(2z+4)-3-((3z-6)+5)=0

We multiply parentheses

16z-((3z-6)+5)+32-3=0



We calculate terms in parentheses: -((3z-6)+5), so:

(3z-6)+5

We get rid of parentheses

3z-6+5

We add all the numbers together, and all the variables

3z-1

Back to the equation:

-(3z-1)



We add all the numbers together, and all the variables

16z-(3z-1)+29=0

We get rid of parentheses

16z-3z+1+29=0

We add all the numbers together, and all the variables

13z+30=0

We move all terms containing z to the left, all other terms to the right

13z=-30

z=-30/13

z=-2+4/13

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