8(2z+1)=4(7z-1)

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Solution for 8(2z+1)=4(7z-1) equation:


Simplifying
8(2z + 1) = 4(7z + -1)

Reorder the terms:
8(1 + 2z) = 4(7z + -1)
(1 * 8 + 2z * 8) = 4(7z + -1)
(8 + 16z) = 4(7z + -1)

Reorder the terms:
8 + 16z = 4(-1 + 7z)
8 + 16z = (-1 * 4 + 7z * 4)
8 + 16z = (-4 + 28z)

Solving
8 + 16z = -4 + 28z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-28z' to each side of the equation.
8 + 16z + -28z = -4 + 28z + -28z

Combine like terms: 16z + -28z = -12z
8 + -12z = -4 + 28z + -28z

Combine like terms: 28z + -28z = 0
8 + -12z = -4 + 0
8 + -12z = -4

Add '-8' to each side of the equation.
8 + -8 + -12z = -4 + -8

Combine like terms: 8 + -8 = 0
0 + -12z = -4 + -8
-12z = -4 + -8

Combine like terms: -4 + -8 = -12
-12z = -12

Divide each side by '-12'.
z = 1

Simplifying
z = 1

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